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execution timing of the method

I might be wrong but since I have not found anygroup newsgroup dedicated to PyQt5.

My small program is expected to show a window GUI for 4 seconds before changing it, so I naively coded:

# codes to set up the GUI
... # F0 being a QMainWindow object
# codes to change the GUI set up


What happens: The a blank window is displayed, freezes for 4 seconds then second set up is displayed, the original set up is not displayed.

Why is not the original set up displayed? 

Obviously, if I remove the codes for the second set up, and the "time.sleep(4)" instruction, the original set up is displayed immediatly after I launch the execution.